Allegiant Air G45472 Flight Status Today

Domestic flight Allegiant Air G45472 takes off from Knoxville (TYS) United States to Orlando (SFB) United States. It's operated by Allegiant Air. The plane leaves McGhee Tyson Airport at 14:52 America/New_York. The flight is expected to land at Orlando Sanford International Airport at None America/New_York. The flight will last about 1 hours 9 minutes.

G45472 - AAY5472 Allegiant Air (G4)
TYS Knoxville United States
Flight TYS to SFB
SFB Orlando United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 14:52
None None
Arrival Orlando Sanford International Airport
IATA: SFBICAO: KSFB
Scheduled None
None None
G45472 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 9 minutes
  • Flight Distance: 821 kms / 510 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319-111
  • Callsign: AAY5472
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Knoxville: Sunday 2026-04-12 12:52 PM
  • Current Time in Orlando: Sunday 2026-04-12 12:52 PM

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Allegiant Air Flight G45472 FAQs

What is the scheduled flight duration for Allegiant Air G45472 flight?

On average, nonstop flight takes 1 hour(s) 9 minutes, with the flight distance of 821 km (510 miles).

What type of aircraft is used for the Allegiant Air G45472 flight?

All Allegiant Air G45472 flights are operated using Airbus A319-111 aircraft.