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Allegiant Air G43052 Flight Status Today
Domestic flight Allegiant Air G43052 takes off from Middletown (MDT) United States to Jacksonville (JAX) United States. It's operated by Allegiant Air. The plane leaves Harrisburg International Airport at 13:02 30 December 2025 America/New_York. The flight is expected to land at Jacksonville International Airport at 14:55 30 December 2025 America/New_York. The flight will last about 1 hours 53 minutes.
Current status of G43052 is Scheduled On time Estimated Depart in 2 hours, 45 minutes
- Type: Domestic Flight
- Flight Duration: 1 hours 53 minutes
- Flight Distance: 1166 kms / 724 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320
- Callsign: F-KMCO1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Middletown: Tuesday 2025-12-30 10:17 AM
- Current Time in Jacksonville: Tuesday 2025-12-30 10:17 AM
Flight routes similar to Allegiant Air G43052
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G43053 Allegiant Air |
30/12/2025 18:09 |
2 hours 1 minutes 20:10 |
Allegiant Air Flight G43052 FAQs
What is the scheduled flight duration for Allegiant Air G43052 flight?
On average, nonstop flight takes 1 hour(s) 53 minutes, with the flight distance of 1166 km (724 miles).
What is the current status of Allegiant Air G43052 flight?
The current status of flight Allegiant Air G43052 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G43052 flight?
All Allegiant Air G43052 flights are operated using Airbus A320 aircraft.
How many Allegiant Air G43052 flights are operated a week?
1 flights per week. The Flight Allegiant Air G43052 is operated on Monday.
