Allegiant Air G43058 Flight Status Today

Domestic flight Allegiant Air G43058 takes off from Knoxville (TYS) United States to Orlando (SFB) United States. It's operated by Allegiant Air. The plane leaves McGhee Tyson Airport at 21:46 America/New_York. The flight is expected to land at Orlando Sanford International Airport at 23:20 America/New_York. The flight will last about 1 hours 34 minutes.

G43058 - AAY3058 Allegiant Air (G4)
TYS Knoxville United States
Flight TYS to SFB
SFB Orlando United States
Contact Airlines It may not operate on the date requested
Departure McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 21:46
None 2
Arrival Orlando Sanford International Airport
IATA: SFBICAO: KSFB
Scheduled 23:20
None 8
G43058 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 34 minutes
  • Flight Distance: 821 kms / 510 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KHXD2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Knoxville: Wednesday 2026-04-29 04:57 AM
  • Current Time in Orlando: Wednesday 2026-04-29 04:57 AM

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Allegiant Air Flight G43058 FAQs

What is the scheduled flight duration for Allegiant Air G43058 flight?

On average, nonstop flight takes 1 hour(s) 34 minutes, with the flight distance of 821 km (510 miles).

What type of aircraft is used for the Allegiant Air G43058 flight?

All Allegiant Air G43058 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G43058 flights are operated a week?

2 flights per week. The Flight Allegiant Air G43058 is operated on Monday, Saturday.