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Allegiant Air G43058 Flight Status Today
Domestic flight Allegiant Air G43058 takes off from Middletown (MDT) United States to Jacksonville (JAX) United States. It's operated by Allegiant Air. The plane leaves Harrisburg International Airport at 07:00 05 March 2026 America/New_York. The flight is expected to land at Jacksonville International Airport at 08:35 05 March 2026 America/New_York. The flight will last about 1 hours 35 minutes.
Current status of G43058 is Arrived On time
G43058 - AAY3058
Allegiant Air (G4)
MDT
Middletown United States
JAX
Jacksonville United States
Arrived On time
Scheduled
07:00 05 March 2026
Actual
06:48 05 March 2026
None
2
Scheduled
08:35 05 March 2026
Actual
08:11 05 March 2026
None
14
G43058 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 35 minutes
- Flight Distance: 1166 kms / 724 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Saturday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Airbus A320
- Callsign: F-KHXD2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Middletown: Thursday 2026-03-05 08:15 AM
- Current Time in Jacksonville: Thursday 2026-03-05 08:15 AM
Allegiant Air Flight G43058 FAQs
What is the scheduled flight duration for Allegiant Air G43058 flight?
On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 1166 km (724 miles).
What is the current status of Allegiant Air G43058 flight?
The current status of flight Allegiant Air G43058 is Arrived On time.
What type of aircraft is used for the Allegiant Air G43058 flight?
All Allegiant Air G43058 flights are operated using Airbus A320 aircraft.
How many Allegiant Air G43058 flights are operated a week?
2 flights per week. The Flight Allegiant Air G43058 is operated on Monday, Saturday.