Allegiant Air G41410 Flight Status Today

Domestic flight Allegiant Air G41410 takes off from Orlando (SFB) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves Orlando Sanford International Airport at 16:56 America/New_York. The flight is expected to land at McGhee Tyson Airport at 18:36 America/New_York. The flight will last about 1 hours 37 minutes.

G41410 - AAY1410 Allegiant Air (G4)
SFB Orlando United States
Flight SFB to TYS
TYS Knoxville United States
Contact Airlines It may not operate on the date requested
Departure Orlando Sanford International Airport
IATA: SFBICAO: KSFB
Scheduled 16:56
None 10
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 18:36
None 6
G41410 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 37 minutes
  • Flight Distance: 821 kms / 510 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Wednesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KFLL2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Orlando: Monday 2026-01-19 01:23 AM
  • Current Time in Knoxville: Monday 2026-01-19 01:23 AM

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Allegiant Air Flight G41410 FAQs

What is the scheduled flight duration for Allegiant Air G41410 flight?

On average, nonstop flight takes 1 hour(s) 37 minutes, with the flight distance of 821 km (510 miles).

What type of aircraft is used for the Allegiant Air G41410 flight?

All Allegiant Air G41410 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G41410 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41410 is operated on Wednesday.