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Allegiant Air G43046 Flight Status Today
Domestic flight Allegiant Air G43046 takes off from Jacksonville (JAX) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves Jacksonville International Airport at 13:38 02 March 2026 America/New_York. The flight is expected to land at Harrisburg International Airport at 15:21 02 March 2026 America/New_York. The flight will last about 4 hours 43 minutes.
Current status of G43046 is Departed On time Estimated Arrival in 45 minutes
- Type: Domestic Flight
- Flight Duration: 4 hours 43 minutes
- Flight Distance: 1166 kms / 724 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320
- Callsign: F-KECP1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Jacksonville: Monday 2026-03-02 14:00 PM
- Current Time in Middletown: Monday 2026-03-02 14:00 PM
Allegiant Air Flight G43046 FAQs
What is the scheduled flight duration for Allegiant Air G43046 flight?
On average, nonstop flight takes 4 hour(s) 43 minutes, with the flight distance of 1166 km (724 miles).
What is the current status of Allegiant Air G43046 flight?
The current status of flight Allegiant Air G43046 is Departed On time.
What type of aircraft is used for the Allegiant Air G43046 flight?
All Allegiant Air G43046 flights are operated using Airbus A320 aircraft.
When does the flight Allegiant Air G43046 arrive?
Flight Allegiant Air G43046 arrives at 15:21.
Which terminal the flight Allegiant Air G43046 is arriving at?
Flight Allegiant Air G43046 arrives in Harrisburg International Airport at Terminal 1.
How many Allegiant Air G43046 flights are operated a week?
2 flights per week. The Flight Allegiant Air G43046 is operated on Thursday, Sunday.
