Allegiant Air G44960 Flight Status Today

Domestic flight Allegiant Air G44960 takes off from Saint Petersburg (PIE) United States to Asheville (AVL) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 12:55 America/New_York. The flight is expected to land at Asheville Regional Airport at 14:28 America/New_York. The flight will last about 1 hours 31 minutes.

G44960 - AAY4960 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to AVL
AVL Asheville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 12:55
None 4
Arrival Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 14:28
None 7
G44960 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 31 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 156
  • Freight capacity: 6.7 tons
  • Passenger classes: First Class, Economy, Business Class
More Detail
  • Aircraft: Airbus A319
  • Callsign: AAY960
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Wednesday 2025-12-31 01:07 AM
  • Current Time in Asheville: Wednesday 2025-12-31 01:07 AM

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Allegiant Air Flight G44960 FAQs

What is the scheduled flight duration for Allegiant Air G44960 flight?

On average, nonstop flight takes 1 hour(s) 31 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G44960 flight?

All Allegiant Air G44960 flights are operated using Airbus A319 aircraft.