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Allegiant Air G41045 Flight Status Today
Domestic flight Allegiant Air G41045 takes off from Saint Petersburg (PIE) United States to Memphis (MEM) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 12:56 America/New_York. The flight is expected to land at Memphis International Airport at 14:02 America/Chicago. The flight will last about 1 hours 56 minutes.
G41045 - AAY1045
Allegiant Air (G4)
PIE
Saint Petersburg United States
MEM
Memphis United States
Contact Airlines
It may not operate on the date requested
Scheduled
12:56
None
3
G41045 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 56 minutes
- Flight Distance: 1050 kms / 653 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday, Sunday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KCHS2
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Saint Petersburg: Sunday 2026-04-05 17:35 PM
- Current Time in Memphis: Sunday 2026-04-05 16:35 PM
Allegiant Air Flight G41045 FAQs
What is the scheduled flight duration for Allegiant Air G41045 flight?
On average, nonstop flight takes 1 hour(s) 56 minutes, with the flight distance of 1050 km (653 miles).
What type of aircraft is used for the Allegiant Air G41045 flight?
All Allegiant Air G41045 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41045 flights are operated a week?
2 flights per week. The Flight Allegiant Air G41045 is operated on Thursday, Sunday.
