Allegiant Air G4236 Flight Status Today

Domestic flight Allegiant Air G4236 takes off from Saint Petersburg (PIE) United States to Asheville (AVL) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 10:01 America/New_York. The flight is expected to land at Asheville Regional Airport at 11:35 America/New_York. The flight will last about 1 hours 34 minutes.

G4236 - AAY236 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to AVL
AVL Asheville United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 10:01
None 10
Arrival Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 11:35
None None
G4236 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 34 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: F-KSRQ2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Monday 2025-12-29 10:48 AM
  • Current Time in Asheville: Monday 2025-12-29 10:48 AM

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18:48

Allegiant Air Flight G4236 FAQs

What is the scheduled flight duration for Allegiant Air G4236 flight?

On average, nonstop flight takes 1 hour(s) 34 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G4236 flight?

All Allegiant Air G4236 flights are operated using Airbus A320 (sharklets) aircraft.

How many Allegiant Air G4236 flights are operated a week?

1 flights per week. The Flight Allegiant Air G4236 is operated on Thursday.