Allegiant Air G43053 flight status now

G43053 - AAY3053 Allegiant Air (G4)
MDT Middletown United States
Flight MDT to JAX
JAX Jacksonville United States
Contact Airlines It may not operate on the date requested
Departure Harrisburg International Airport
IATA: MDTICAO: KMDT
Scheduled 18:09
None B6
Arrival Jacksonville International Airport
IATA: JAXICAO: KJAX
Scheduled 20:10
None C6
G43053 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 1 minutes
  • Flight Distance: 1166 kms / 724 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Wednesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KCTY2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Middletown: Thursday 2025-11-20 03:37 AM
  • Current Time in Jacksonville: Thursday 2025-11-20 03:37 AM

Domestic flight Allegiant Air G43053 takes off from Middletown (MDT) United States to Jacksonville (JAX) United States. It's operated by Allegiant Air. The plane leaves Harrisburg International Airport at 18:09 America/New_York. The flight is expected to land at Jacksonville International Airport at 20:10 America/New_York. The flight will last about 2 hours 1 minutes.

Similar flight route from Middletown (MDT) to Jacksonville (JAX)

Airline Flight no Departure Arrival
Allegiant Air G43049
Allegiant Air 		20/11/2025
18:09 		2 hours 1 minutes
20:10

Frequently asked questions, answered

How long is the flight from Middletown to Jacksonville?

On average, nonstop flight takes 2 hour(s) 1 minutes, with the flight distance of 1166 km (724 miles).

What type of aircraft is used for the Allegiant Air G43053 flight?

All Allegiant Air G43053 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G43053 flights are operated a week?

1 flights per week. The Flight Allegiant Air G43053 is operated on Wednesday.