Allegiant Air G42108 Flight Status Today

Domestic flight Allegiant Air G42108 takes off from Fort Lauderdale (FLL) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves Fort Lauderdale-Hollywood International Airport at 07:40 America/New_York. The flight is expected to land at McGhee Tyson Airport at 09:50 America/New_York. The flight will last about 2 hours 10 minutes.

G42108 - AAY2108 Allegiant Air (G4)
FLL Fort Lauderdale United States
Flight FLL to TYS
TYS Knoxville United States
Contact Airlines It may not operate on the date requested
Departure Fort Lauderdale-Hollywood International Airport
IATA: FLLICAO: KFLL
Scheduled 07:40
1 None
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 09:50
None None
G42108 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 10 minutes
  • Flight Distance: 1140 kms / 708 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KRMG1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Fort Lauderdale: Friday 2026-04-10 15:03 PM
  • Current Time in Knoxville: Friday 2026-04-10 15:03 PM

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Allegiant Air Flight G42108 FAQs

What is the scheduled flight duration for Allegiant Air G42108 flight?

On average, nonstop flight takes 2 hour(s) 10 minutes, with the flight distance of 1140 km (708 miles).

What type of aircraft is used for the Allegiant Air G42108 flight?

All Allegiant Air G42108 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G42108 flights are operated a week?

1 flights per week. The Flight Allegiant Air G42108 is operated on Thursday.