Check your Flight status online
Allegiant Air G43039 Flight Status Today
Domestic flight Allegiant Air G43039 takes off from Jacksonville (JAX) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves Jacksonville International Airport at 13:21 22 March 2026 America/New_York. The flight is expected to land at Harrisburg International Airport at 15:18 22 March 2026 America/New_York. The flight will last about 2 hours 3 minutes.
Current status of G43039 is Arrived On time
- Type: Domestic Flight
- Flight Duration: 2 hours 3 minutes
- Flight Distance: 1166 kms / 724 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday, Friday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KRMG1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Jacksonville: Sunday 2026-03-22 19:54 PM
- Current Time in Middletown: Sunday 2026-03-22 19:54 PM
Flight routes similar to Allegiant Air G43039
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G43795 Allegiant Air |
22/03/2026 09:25 |
1 hours 58 minutes 11:30 |
Allegiant Air Flight G43039 FAQs
What is the scheduled flight duration for Allegiant Air G43039 flight?
On average, nonstop flight takes 2 hour(s) 3 minutes, with the flight distance of 1166 km (724 miles).
What is the current status of Allegiant Air G43039 flight?
The current status of flight Allegiant Air G43039 is Arrived On time.
What type of aircraft is used for the Allegiant Air G43039 flight?
All Allegiant Air G43039 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G43039 flights are operated a week?
3 flights per week. The Flight Allegiant Air G43039 is operated on Thursday, Friday, Sunday.
