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Allegiant Air G43039 Flight Status Today
Domestic flight Allegiant Air G43039 takes off from Jacksonville (JAX) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves Jacksonville International Airport at 14:09 America/New_York. The flight is expected to land at Harrisburg International Airport at 16:10 America/New_York. The flight will last about 2 hours 1 minutes.
G43039 - AAY3039
Allegiant Air (G4)
JAX
Jacksonville United States
MDT
Middletown United States
Contact Airlines
It may not operate on the date requested
G43039 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 1 minutes
- Flight Distance: 1166 kms / 724 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday, Friday, Sunday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KRMG1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Jacksonville: Sunday 2026-03-01 05:31 AM
- Current Time in Middletown: Sunday 2026-03-01 05:31 AM
Allegiant Air Flight G43039 FAQs
What is the scheduled flight duration for Allegiant Air G43039 flight?
On average, nonstop flight takes 2 hour(s) 1 minutes, with the flight distance of 1166 km (724 miles).
What type of aircraft is used for the Allegiant Air G43039 flight?
All Allegiant Air G43039 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G43039 flights are operated a week?
3 flights per week. The Flight Allegiant Air G43039 is operated on Thursday, Friday, Sunday.
