FedEx FX7231 flight status now

FX7231 - FDX7231 FedEx Express (FX)
IND Indianapolis United States
Flight IND to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 11:52
None None
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled None
None None
FX7231 Detail
  • Type: Domestic Flight
  • Flight Duration: 44 minutes
  • Flight Distance: 422 kms / 262 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A300F4-605R
  • Callsign: FDX7231
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Tuesday 2025-11-18 13:54 PM
  • Current Time in Cleveland: Tuesday 2025-11-18 13:54 PM

Domestic flight FedEx FX7231 takes off from Indianapolis (IND) United States to Cleveland (CLE) United States. It's operated by FedEx Express. The plane leaves Indianapolis International Airport at 11:52 America/Indiana/Indianapolis. The flight is expected to land at Cleveland Hopkins International Airport at None America/New_York. The flight will last about 44 minutes.

Similar flight route from Indianapolis (IND) to Cleveland (CLE)

Airline Flight no Departure Arrival
FedEx FX1731
FedEx 		18/11/2025
04:47 		0 minutes
05:30
American Airlines AA9694
American Airlines 		18/11/2025
16:00 		1 hours 3 minutes
17:15

Frequently asked questions, answered

How long is the flight from Indianapolis to Cleveland?

On average, nonstop flight takes 44 minutes, with the flight distance of 422 km (262 miles).

What type of aircraft is used for the FedEx FX7231 flight?

All FedEx FX7231 flights are operated using Airbus A300F4-605R aircraft.