FedEx FX1731 flight status now

FX1731 - FDX1731 FedEx Express (FX)
IND Indianapolis United States
Flight IND to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 04:47
None None
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 05:30
None None
FX1731 Detail
  • Type: Domestic Flight
  • Flight Duration: 0 minutes
  • Flight Distance: 422 kms / 262 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: Tuesday, Wednesday, Thursday, Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 767-300 Passenger
  • Callsign: F-KCLE4
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Monday 2025-11-17 14:24 PM
  • Current Time in Cleveland: Monday 2025-11-17 14:24 PM

Domestic flight FedEx FX1731 takes off from Indianapolis (IND) United States to Cleveland (CLE) United States. It's operated by FedEx Express. The plane leaves Indianapolis International Airport at 04:47 America/Indiana/Indianapolis. The flight is expected to land at Cleveland Hopkins International Airport at 05:30 America/New_York. The flight will last about 0 minutes.

Similar flight route from Indianapolis (IND) to Cleveland (CLE)

Airline Flight no Departure Arrival
American Airlines AA9694
American Airlines 		17/11/2025
16:00 		1 hours 3 minutes
17:15

Frequently asked questions, answered

How long is the flight from Indianapolis to Cleveland?

On average, nonstop flight takes 0 minutes, with the flight distance of 422 km (262 miles).

What type of aircraft is used for the FedEx FX1731 flight?

All FedEx FX1731 flights are operated using Boeing 767-300 Passenger aircraft.

How many FedEx FX1731 flights are operated a week?

4 flights per week. The Flight FedEx FX1731 is operated on Tuesday, Wednesday, Thursday, Friday.