FedEx FX2731 Flight Status Today

Domestic flight FedEx FX2731 takes off from Indianapolis (IND) United States to Cleveland (CLE) United States. It's operated by FedEx Express. The plane leaves Indianapolis International Airport at 09:26 America/Indiana/Indianapolis. The flight is expected to land at Cleveland Hopkins International Airport at 10:10 America/New_York. The flight will last about 1 hours 5 minutes.

FX2731 - FDX2731 FedEx Express (FX)
IND Indianapolis United States
Flight IND to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 28-February-2021
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 09:26
None None
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 10:10
None None
FX2731 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 5 minutes
  • Flight Distance: 422 kms / 262 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A300-600 Freighter
  • Callsign: FDX2731
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Wednesday 2025-12-31 22:11 PM
  • Current Time in Cleveland: Wednesday 2025-12-31 22:11 PM

Flight routes similar to FedEx FX2731

Airline Flight no Departure Arrival
FedEx FX1731
FedEx 		31/12/2025
04:47 		1 hours 21 minutes
05:30
American Airlines AA9694
American Airlines 		31/12/2025
16:00 		1 hours 3 minutes
17:15

FedEx Flight FX2731 FAQs

What is the scheduled flight duration for FedEx FX2731 flight?

On average, nonstop flight takes 1 hour(s) 5 minutes, with the flight distance of 422 km (262 miles).

What type of aircraft is used for the FedEx FX2731 flight?

All FedEx FX2731 flights are operated using Airbus A300-600 Freighter aircraft.