FedEx FX2731 flight status now

FX2731 - FDX2731 FedEx Express (FX)
IND Indianapolis United States
Flight IND to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 28-February-2021
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 09:26
None None
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 10:10
None None
FX2731 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 5 minutes
  • Flight Distance: 422 kms / 262 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A300-600 Freighter
  • Callsign: FDX2731
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Tuesday 2025-11-18 15:43 PM
  • Current Time in Cleveland: Tuesday 2025-11-18 15:43 PM

Domestic flight FedEx FX2731 takes off from Indianapolis (IND) United States to Cleveland (CLE) United States. It's operated by FedEx Express. The plane leaves Indianapolis International Airport at 09:26 America/Indiana/Indianapolis. The flight is expected to land at Cleveland Hopkins International Airport at 10:10 America/New_York. The flight will last about 1 hours 5 minutes.

Similar flight route from Indianapolis (IND) to Cleveland (CLE)

Airline Flight no Departure Arrival
FedEx FX1731
FedEx 		18/11/2025
04:47 		0 minutes
05:30
American Airlines AA9694
American Airlines 		18/11/2025
16:00 		1 hours 3 minutes
17:15

Frequently asked questions, answered

How long is the flight from Indianapolis to Cleveland?

On average, nonstop flight takes 1 hour(s) 5 minutes, with the flight distance of 422 km (262 miles).

What type of aircraft is used for the FedEx FX2731 flight?

All FedEx FX2731 flights are operated using Airbus A300-600 Freighter aircraft.