WestJet WS3810 Flight Status Today

Domestic flight WestJet WS3810 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 18:20 America/Vancouver. The flight is expected to land at Calgary International Airport at 20:27 America/Edmonton. The flight will last about 54 minutes.

WS3810 - WJA3810 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 18:20
MA 8
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 20:27
None C58
WS3810 Detail
  • Type: Domestic Flight
  • Flight Duration: 54 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: De Havilland (Bombardier) DHC-8-400 Dash 8Q
  • Callsign: None
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Sunday 2026-01-18 10:13 AM
  • Current Time in Calgary: Sunday 2026-01-18 11:13 AM

Flight routes similar to WestJet WS3810

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WestJet WS3608
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Delta DL6959
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Delta DL6997
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WestJet WS3610
WestJet 		18/01/2026
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WestJet Flight WS3810 FAQs

What is the scheduled flight duration for WestJet WS3810 flight?

On average, nonstop flight takes 54 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS3810 flight?

All WestJet WS3810 flights are operated using De Havilland (Bombardier) DHC-8-400 Dash 8Q aircraft.