Delta DL7258 Flight Status Today

Domestic flight Delta DL7258 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by Delta Airlines. The plane leaves Kelowna International Airport at 10:20 America/Vancouver. The flight is expected to land at Calgary International Airport at 12:31 America/Edmonton. The flight will last about 1 hours 4 minutes.

DL7258 - DAL7258 Delta Airlines (DL)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 10:20
MA 8
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 12:31
None A22
DL7258 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 4 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: Friday
Passenger Services
  • Service type: Normal passenger
  • Seats: 176
  • Freight capacity: 8.7 tons
  • Passenger classes: Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Boeing 737-700 (winglets) Passenger/BBJ1
  • Callsign: DAL7258
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Thursday 2026-04-09 18:24 PM
  • Current Time in Calgary: Thursday 2026-04-09 19:24 PM

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Delta Flight DL7258 FAQs

What is the scheduled flight duration for Delta DL7258 flight?

On average, nonstop flight takes 1 hour(s) 4 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the Delta DL7258 flight?

All Delta DL7258 flights are operated using Boeing 737-700 (winglets) Passenger/BBJ1 aircraft.

How many Delta DL7258 flights are operated a week?

1 flights per week. The Flight Delta DL7258 is operated on Friday.