SpiceJet SG4010 Flight Status Today

Domestic flight SpiceJet SG4010 takes off from Hyderabad (HYD) India to Vishakhapatnam (VTZ) India. It's operated by SpiceJet. The plane leaves Rajiv Gandhi International Airport at 21:15 Asia/Kolkata. The flight is expected to land at Vishakhapatnam Airport at 22:30 Asia/Kolkata. The flight will last about 1 hours 15 minutes.

SG4010 - SEJ4010 SpiceJet (SG)
HYD Hyderabad India
Flight HYD to VTZ
VTZ Vishakhapatnam India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 27-March-2022
Departure Rajiv Gandhi International Airport
IATA: HYDICAO: VOHS
Scheduled 21:15
None 85
Arrival Vishakhapatnam Airport
IATA: VTZICAO: VEVZ
Scheduled 22:30
None None
SG4010 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 15 minutes
  • Flight Distance: 512 kms / 318 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: De Havilland (Bombardier) DHC-8-400 Dash 8Q
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Hyderabad: Monday 2026-01-19 04:27 AM
  • Current Time in Vishakhapatnam: Monday 2026-01-19 04:27 AM

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SpiceJet Flight SG4010 FAQs

What is the scheduled flight duration for SpiceJet SG4010 flight?

On average, nonstop flight takes 1 hour(s) 15 minutes, with the flight distance of 512 km (318 miles).

What type of aircraft is used for the SpiceJet SG4010 flight?

All SpiceJet SG4010 flights are operated using De Havilland (Bombardier) DHC-8-400 Dash 8Q aircraft.