Air India AI9408 Flight Status Today

Domestic flight Air India AI9408 takes off from Hyderabad (HYD) India to Vishakhapatnam (VTZ) India. It's operated by Air India. The plane leaves Rajiv Gandhi International Airport at 12:45 29 December 2025 Asia/Kolkata. The flight is expected to land at Vishakhapatnam Airport at 14:15 29 December 2025 Asia/Kolkata. The flight will last about 1 hours 30 minutes.

Current status of AI9408 is Scheduled On time Expected Depart in 11 hours, 41 minutes

AI9408 - AIC9408 Air India (AI)
HYD Hyderabad India
Flight HYD to VTZ
VTZ Vishakhapatnam India
Scheduled On time Expected Depart in 11 hours, 41 minutes
Departure Rajiv Gandhi International Airport
IATA: HYDICAO: VOHS
Scheduled 12:45 29 December 2025
None 8
Arrival Vishakhapatnam Airport
IATA: VTZICAO: VEVZ
Scheduled 14:15 29 December 2025
None None
AI9408 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 30 minutes
  • Flight Distance: 512 kms / 318 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: Sunday
Passenger Services
  • Service type: N/A
  • Seats: N/A
  • Freight capacity: N/A
  • Passenger classes: N/A
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: N/A
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Hyderabad: Monday 2025-12-29 01:04 AM
  • Current Time in Vishakhapatnam: Monday 2025-12-29 01:04 AM

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Air India Flight AI9408 FAQs

What is the scheduled flight duration for Air India AI9408 flight?

On average, nonstop flight takes 1 hour(s) 30 minutes, with the flight distance of 512 km (318 miles).

What is the current status of Air India AI9408 flight?

The current status of flight Air India AI9408 is Scheduled On time.

What type of aircraft is used for the Air India AI9408 flight?

All Air India AI9408 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Air India AI9408 flights are operated a week?

1 flights per week. The Flight Air India AI9408 is operated on Sunday.