Jazz QK248 Flight Status Today

Domestic flight Jazz QK248 takes off from Regina (YQR) Canada to Calgary (YYC) Canada. It's operated by Jazz. The plane leaves Regina International Airport at 18:00 America/Regina. The flight is expected to land at Calgary International Airport at 18:00 America/Edmonton. The flight will last about 1 hours 11 minutes.

QK248 - JZA248 Jazz (QK)
YQR Regina Canada
Flight YQR to YYC
YYC Calgary Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 02-June-2022
Departure Regina International Airport
IATA: YQRICAO: CYQR
Scheduled 18:00
None None
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 18:00
None None
QK248 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 11 minutes
  • Flight Distance: 664 kms / 413 miles
Airline
  • Jazz
  • IATA: QK
  • ICAO: JZA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: CRJ9
  • Callsign: JZA248
  • Departure Timezone: America/Regina
  • Arrival Timezone: America/Edmonton
  • Current Time in Regina: Friday 2026-05-01 17:55 PM
  • Current Time in Calgary: Friday 2026-05-01 17:55 PM

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Jazz Flight QK248 FAQs

What is the scheduled flight duration for Jazz QK248 flight?

On average, nonstop flight takes 1 hour(s) 11 minutes, with the flight distance of 664 km (413 miles).

What type of aircraft is used for the Jazz QK248 flight?

All Jazz QK248 flights are operated using CRJ9 aircraft.