Delta DL6955 Flight Status Today

Domestic flight Delta DL6955 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by Delta Airlines. The plane leaves Kelowna International Airport at 08:50 America/Vancouver. The flight is expected to land at Calgary International Airport at 11:05 America/Edmonton. The flight will last about 1 hours 8 minutes.

DL6955 - DAL6955 Delta Airlines (DL)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 08:50
MA 8
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 11:05
None A20
DL6955 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 8 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: Monday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 177
  • Freight capacity: 0 tons
  • Passenger classes: Economy, Business Class
More Detail
  • Aircraft: De Havilland (Bombardier) DHC-8-400 Dash 8Q
  • Callsign: DAL6955
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Saturday 2026-04-11 00:01 AM
  • Current Time in Calgary: Saturday 2026-04-11 01:01 AM

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Delta Flight DL6955 FAQs

What is the scheduled flight duration for Delta DL6955 flight?

On average, nonstop flight takes 1 hour(s) 8 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the Delta DL6955 flight?

All Delta DL6955 flights are operated using De Havilland (Bombardier) DHC-8-400 Dash 8Q aircraft.

How many Delta DL6955 flights are operated a week?

6 flights per week. The Flight Delta DL6955 is operated on Monday, Wednesday, Thursday, Friday, Saturday, Sunday.