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Allegiant Air G4984 Flight Status Today
Domestic flight Allegiant Air G4984 takes off from Clarksburg (CKB) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Benedum Airport at 18:23 23 March 2026 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 20:33 23 March 2026 America/New_York. The flight will last about 2 hours 10 minutes.
Current status of G4984 is Scheduled On time Expected Depart in 10 hours, 14 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 10 minutes
- Flight Distance: 1283 kms / 797 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A319
- Callsign: F-KRMG1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Clarksburg: Monday 2026-03-23 08:09 AM
- Current Time in Saint Petersburg: Monday 2026-03-23 08:09 AM
Allegiant Air Flight G4984 FAQs
What is the scheduled flight duration for Allegiant Air G4984 flight?
On average, nonstop flight takes 2 hour(s) 10 minutes, with the flight distance of 1283 km (797 miles).
What is the current status of Allegiant Air G4984 flight?
The current status of flight Allegiant Air G4984 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G4984 flight?
All Allegiant Air G4984 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G4984 flights are operated a week?
6 flights per week. The Flight Allegiant Air G4984 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Sunday.
