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Allegiant Air G4984 Flight Status Today
Domestic flight Allegiant Air G4984 takes off from Saint Petersburg (PIE) United States to Clarksburg (CKB) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 18:23 America/New_York. The flight is expected to land at Benedum Airport at 20:33 America/New_York. The flight will last about 2 hours 10 minutes.
G4984 - AAY984
Allegiant Air (G4)
PIE
Saint Petersburg United States
CKB
Clarksburg United States
Contact Airlines
It may not operate on the date requested
Scheduled
18:23
None
10
G4984 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 10 minutes
- Flight Distance: 1283 kms / 797 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Sunday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KRMG1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Thursday 2026-04-16 08:05 AM
- Current Time in Clarksburg: Thursday 2026-04-16 08:05 AM
Flight routes similar to Allegiant Air G4984
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G42708 Allegiant Air |
16/04/2026 18:07 |
2 hours 12 minutes 20:19 |
Allegiant Air Flight G4984 FAQs
What is the scheduled flight duration for Allegiant Air G4984 flight?
On average, nonstop flight takes 2 hour(s) 10 minutes, with the flight distance of 1283 km (797 miles).
What type of aircraft is used for the Allegiant Air G4984 flight?
All Allegiant Air G4984 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G4984 flights are operated a week?
6 flights per week. The Flight Allegiant Air G4984 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Sunday.