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Allegiant Air G42708 Flight Status Today
Domestic flight Allegiant Air G42708 takes off from Newburgh (SWF) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Stewart International Airport at 20:40 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 23:38 America/New_York. The flight will last about 2 hours 58 minutes.
G42708 - AAY2708
Allegiant Air (G4)
SWF
Newburgh United States
PIE
Saint Petersburg United States
Contact Airlines
It may not operate on the date requested
G42708 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 58 minutes
- Flight Distance: 1698 kms / 1055 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Tuesday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: T-KFWA1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Newburgh: Monday 2026-03-23 02:47 AM
- Current Time in Saint Petersburg: Monday 2026-03-23 02:47 AM
Flight routes similar to Allegiant Air G42708
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G43677 Allegiant Air |
23/03/2026 14:47 |
2 hours 57 minutes 17:44 |
Allegiant Air Flight G42708 FAQs
What is the scheduled flight duration for Allegiant Air G42708 flight?
On average, nonstop flight takes 2 hour(s) 58 minutes, with the flight distance of 1698 km (1055 miles).
What type of aircraft is used for the Allegiant Air G42708 flight?
All Allegiant Air G42708 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G42708 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42708 is operated on Tuesday.
