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Allegiant Air G42708 Flight Status Today
Domestic flight Allegiant Air G42708 takes off from Newburgh (SWF) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Stewart International Airport at 18:07 13 April 2026 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 20:19 13 April 2026 America/New_York. The flight will last about 2 hours 12 minutes.
Current status of G42708 is Scheduled On time Expected Depart in 13 hours, 33 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 12 minutes
- Flight Distance: 1698 kms / 1055 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Tuesday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: T-KFWA1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Newburgh: Monday 2026-04-13 04:34 AM
- Current Time in Saint Petersburg: Monday 2026-04-13 04:34 AM
Allegiant Air Flight G42708 FAQs
What is the scheduled flight duration for Allegiant Air G42708 flight?
On average, nonstop flight takes 2 hour(s) 12 minutes, with the flight distance of 1698 km (1055 miles).
What is the current status of Allegiant Air G42708 flight?
The current status of flight Allegiant Air G42708 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G42708 flight?
All Allegiant Air G42708 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G42708 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42708 is operated on Tuesday.
