Allegiant Air G4607 Flight Status Today

Domestic flight Allegiant Air G4607 takes off from Indianapolis (IND) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Indianapolis International Airport at 08:00 America/Indiana/Indianapolis. The flight is expected to land at St. Petersburg-Clearwater International Airport at 10:21 America/New_York. The flight will last about 2 hours 50 minutes.

G4607 - AAY607 Allegiant Air (G4)
IND Indianapolis United States
Flight IND to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 08:00
None B3
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 10:21
None 5
G4607 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 50 minutes
  • Flight Distance: 1351 kms / 839 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KMRN1
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Sunday 2026-03-22 06:46 AM
  • Current Time in Saint Petersburg: Sunday 2026-03-22 06:46 AM

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Allegiant Air Flight G4607 FAQs

What is the scheduled flight duration for Allegiant Air G4607 flight?

On average, nonstop flight takes 2 hour(s) 50 minutes, with the flight distance of 1351 km (839 miles).

What type of aircraft is used for the Allegiant Air G4607 flight?

All Allegiant Air G4607 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G4607 flights are operated a week?

1 flights per week. The Flight Allegiant Air G4607 is operated on Thursday.