Allegiant Air G42236 Flight Status Today

Domestic flight Allegiant Air G42236 takes off from Jacksonville (JAX) United States to Indianapolis (IND) United States. It's operated by Allegiant Air. The plane leaves Jacksonville International Airport at 12:05 America/New_York. The flight is expected to land at Indianapolis International Airport at 14:11 America/Indiana/Indianapolis. The flight will last about 1 hours 59 minutes.

G42236 - AAY2236 Allegiant Air (G4)
JAX Jacksonville United States
Flight JAX to IND
IND Indianapolis United States
Contact Airlines It may not operate on the date requested
Departure Jacksonville International Airport
IATA: JAXICAO: KJAX
Scheduled 12:05
None C6
Arrival Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 14:11
None B4
G42236 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 59 minutes
  • Flight Distance: 1106 kms / 687 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KCHA2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Indiana/Indianapolis
  • Current Time in Jacksonville: Monday 2026-01-19 08:29 AM
  • Current Time in Indianapolis: Monday 2026-01-19 08:29 AM

Flight routes similar to Allegiant Air G42236

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Allegiant Air Flight G42236 FAQs

What is the scheduled flight duration for Allegiant Air G42236 flight?

On average, nonstop flight takes 1 hour(s) 59 minutes, with the flight distance of 1106 km (687 miles).

What type of aircraft is used for the Allegiant Air G42236 flight?

All Allegiant Air G42236 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G42236 flights are operated a week?

1 flights per week. The Flight Allegiant Air G42236 is operated on Thursday.