Allegiant Air G45838 Flight Status Today

Domestic flight Allegiant Air G45838 takes off from Columbus (LCK) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Rickenbacker International Airport at 09:30 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 11:45 America/New_York. The flight will last about 2 hours 8 minutes.

G45838 - AAY5838 Allegiant Air (G4)
LCK Columbus United States
Flight LCK to PIE
PIE Saint Petersburg United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 14-December-2020
Departure Rickenbacker International Airport
IATA: LCKICAO: KLCK
Scheduled 09:30
None 2
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 11:45
None 9
G45838 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 8 minutes
  • Flight Distance: 1321 kms / 821 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: AAY5838
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Columbus: Thursday 2026-01-01 12:26 PM
  • Current Time in Saint Petersburg: Thursday 2026-01-01 12:26 PM

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Allegiant Air Flight G45838 FAQs

What is the scheduled flight duration for Allegiant Air G45838 flight?

On average, nonstop flight takes 2 hour(s) 8 minutes, with the flight distance of 1321 km (821 miles).

What type of aircraft is used for the Allegiant Air G45838 flight?

All Allegiant Air G45838 flights are operated using Airbus A320 (sharklets) aircraft.