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Allegiant Air G42693 Flight Status Today
Domestic flight Allegiant Air G42693 takes off from Saint Petersburg (PIE) United States to Akron (CAK) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 19:50 25 March 2026 America/New_York. The flight is expected to land at Akron-Canton Airport at 22:05 25 March 2026 America/New_York. The flight will last about 2 hours 15 minutes.
Current status of G42693 is Scheduled On time Expected Depart in 17 hours, 59 minutes
G42693 - AAY2693
Allegiant Air (G4)
PIE
Saint Petersburg United States
CAK
Akron United States
Scheduled On time
Expected Depart in 17 hours, 59 minutes
Scheduled
19:50 25 March 2026
None
None
G42693 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 15 minutes
- Flight Distance: 1447 kms / 899 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KMSV1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Wednesday 2026-03-25 01:51 AM
- Current Time in Akron: Wednesday 2026-03-25 01:51 AM
Allegiant Air Flight G42693 FAQs
What is the scheduled flight duration for Allegiant Air G42693 flight?
On average, nonstop flight takes 2 hour(s) 15 minutes, with the flight distance of 1447 km (899 miles).
What is the current status of Allegiant Air G42693 flight?
The current status of flight Allegiant Air G42693 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G42693 flight?
All Allegiant Air G42693 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G42693 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42693 is operated on Thursday.