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Allegiant Air G41099 Flight Status Today
Domestic flight Allegiant Air G41099 takes off from Columbus (LCK) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Rickenbacker International Airport at 10:05 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 12:17 America/New_York. The flight will last about 2 hours 12 minutes.
G41099 - AAY1099
Allegiant Air (G4)
LCK
Columbus United States
PIE
Saint Petersburg United States
Contact Airlines
It may not operate on the date requested
G41099 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 12 minutes
- Flight Distance: 1321 kms / 821 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Saturday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A320
- Callsign: F-KSTL3
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Columbus: Wednesday 2026-04-29 23:41 PM
- Current Time in Saint Petersburg: Wednesday 2026-04-29 23:41 PM
Flight routes similar to Allegiant Air G41099
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G42693 Allegiant Air |
29/04/2026 19:50 |
2 hours 15 minutes 22:05 |
Allegiant Air Flight G41099 FAQs
What is the scheduled flight duration for Allegiant Air G41099 flight?
On average, nonstop flight takes 2 hour(s) 12 minutes, with the flight distance of 1321 km (821 miles).
What type of aircraft is used for the Allegiant Air G41099 flight?
All Allegiant Air G41099 flights are operated using Airbus A320 aircraft.
How many Allegiant Air G41099 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41099 is operated on Saturday.
