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Allegiant Air G41099 Flight Status Today
Domestic flight Allegiant Air G41099 takes off from Saint Petersburg (PIE) United States to Rockford (RFD) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 06:40 America/New_York. The flight is expected to land at Chicago Rockford International Airport at 08:32 America/Chicago. The flight will last about 2 hours 52 minutes.
G41099 - AAY1099
Allegiant Air (G4)
PIE
Saint Petersburg United States
RFD
Rockford United States
Contact Airlines
It may not operate on the date requested
Scheduled
06:40
None
11
G41099 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 52 minutes
- Flight Distance: 1688 kms / 1049 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Saturday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KSTL3
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Saint Petersburg: Sunday 2026-04-05 17:35 PM
- Current Time in Rockford: Sunday 2026-04-05 16:35 PM
Flight routes similar to Allegiant Air G41099
Allegiant Air Flight G41099 FAQs
What is the scheduled flight duration for Allegiant Air G41099 flight?
On average, nonstop flight takes 2 hour(s) 52 minutes, with the flight distance of 1688 km (1049 miles).
What type of aircraft is used for the Allegiant Air G41099 flight?
All Allegiant Air G41099 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41099 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41099 is operated on Saturday.
