Allegiant Air G45408 Flight Status Today

Domestic flight Allegiant Air G45408 takes off from Dulles (IAD) United States to Jacksonville (JAX) United States. It's operated by Allegiant Air. The plane leaves Washington Dulles International Airport at 18:54 America/New_York. The flight is expected to land at Jacksonville International Airport at 21:30 America/New_York. The flight will last about 1 hours 52 minutes.

G45408 - AAY5408 Allegiant Air (G4)
IAD Dulles United States
Flight IAD to JAX
JAX Jacksonville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Washington Dulles International Airport
IATA: IADICAO: KIAD
Scheduled 18:54
Arrival Jacksonville International Airport
IATA: JAXICAO: KJAX
Scheduled 21:30
G45408 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 52 minutes
  • Flight Distance: 1015 kms / 631 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320-214
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Dulles: Sunday 2026-03-22 10:55 AM
  • Current Time in Jacksonville: Sunday 2026-03-22 10:55 AM

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Allegiant Air Flight G45408 FAQs

What is the scheduled flight duration for Allegiant Air G45408 flight?

On average, nonstop flight takes 1 hour(s) 52 minutes, with the flight distance of 1015 km (631 miles).

What type of aircraft is used for the Allegiant Air G45408 flight?

All Allegiant Air G45408 flights are operated using Airbus A320-214 aircraft.