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Allegiant Air G42704 Flight Status Today
Domestic flight Allegiant Air G42704 takes off from Saint Petersburg (PIE) United States to Cedar Rapids (CID) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 19:23 23 March 2026 America/New_York. The flight is expected to land at The Eastern Iowa Airport at 22:59 23 March 2026 America/Chicago. The flight will last about 2 hours 36 minutes.
Current status of G42704 is Scheduled On time Expected Depart in 16 hours, 36 minutes
G42704 - AAY2704
Allegiant Air (G4)
PIE
Saint Petersburg United States
CID
Cedar Rapids United States
Scheduled On time
Expected Depart in 16 hours, 36 minutes
Scheduled
19:23 23 March 2026
None
None
G42704 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 36 minutes
- Flight Distance: 1753 kms / 1089 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KUZA1
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Saint Petersburg: Monday 2026-03-23 02:47 AM
- Current Time in Cedar Rapids: Monday 2026-03-23 01:47 AM
Allegiant Air Flight G42704 FAQs
What is the scheduled flight duration for Allegiant Air G42704 flight?
On average, nonstop flight takes 2 hour(s) 36 minutes, with the flight distance of 1753 km (1089 miles).
What is the current status of Allegiant Air G42704 flight?
The current status of flight Allegiant Air G42704 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G42704 flight?
All Allegiant Air G42704 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G42704 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42704 is operated on Monday.