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Allegiant Air G41087 Flight Status Today
Domestic flight Allegiant Air G41087 takes off from Saint Petersburg (PIE) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 14:32 America/New_York. The flight is expected to land at Harrisburg International Airport at 16:56 America/New_York. The flight will last about 2 hours 23 minutes.
G41087 - AAY1087
Allegiant Air (G4)
PIE
Saint Petersburg United States
MDT
Middletown United States
Contact Airlines
It may not operate on the date requested
Scheduled
14:32
None
9
G41087 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 23 minutes
- Flight Distance: 1468 kms / 912 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KMSS1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Sunday 2026-03-01 13:49 PM
- Current Time in Middletown: Sunday 2026-03-01 13:49 PM
Allegiant Air Flight G41087 FAQs
What is the scheduled flight duration for Allegiant Air G41087 flight?
On average, nonstop flight takes 2 hour(s) 23 minutes, with the flight distance of 1468 km (912 miles).
What type of aircraft is used for the Allegiant Air G41087 flight?
All Allegiant Air G41087 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41087 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41087 is operated on Thursday.
