Allegiant Air G41912 Flight Status Today

Domestic flight Allegiant Air G41912 takes off from Saint Petersburg (PIE) United States to Roanoke (ROA) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 12:12 America/New_York. The flight is expected to land at Roanoke-Blacksburg Regional Airport at 14:05 America/New_York. The flight will last about 1 hours 56 minutes.

G41912 - AAY1912 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to ROA
ROA Roanoke United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 23-March-2022
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 12:12
None 2
Arrival Roanoke-Blacksburg Regional Airport
IATA: ROAICAO: KROA
Scheduled 14:05
None 6
G41912 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 56 minutes
  • Flight Distance: 1074 kms / 667 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Monday 2026-01-19 10:06 AM
  • Current Time in Roanoke: Monday 2026-01-19 10:06 AM

Flight routes similar to Allegiant Air G41912

Airline Flight no Departure Arrival
Allegiant Air G41028
Allegiant Air 		19/01/2026
13:15 		2 hours 9 minutes
15:11

Allegiant Air Flight G41912 FAQs

What is the scheduled flight duration for Allegiant Air G41912 flight?

On average, nonstop flight takes 1 hour(s) 56 minutes, with the flight distance of 1074 km (667 miles).

What type of aircraft is used for the Allegiant Air G41912 flight?

All Allegiant Air G41912 flights are operated using Airbus A320 aircraft.