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Allegiant Air G41050 Flight Status Today
Domestic flight Allegiant Air G41050 takes off from Saint Petersburg (PIE) United States to Roanoke (ROA) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 12:09 America/New_York. The flight is expected to land at Roanoke-Blacksburg Regional Airport at 14:08 America/New_York. The flight will last about 1 hours 59 minutes.
G41050 - AAY1050
Allegiant Air (G4)
PIE
Saint Petersburg United States
ROA
Roanoke United States
Contact Airlines
It may not operate on the date requested
Scheduled
12:09
None
9
G41050 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 59 minutes
- Flight Distance: 1074 kms / 667 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Friday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KZPH2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Thursday 2026-04-16 17:15 PM
- Current Time in Roanoke: Thursday 2026-04-16 17:15 PM
Allegiant Air Flight G41050 FAQs
What is the scheduled flight duration for Allegiant Air G41050 flight?
On average, nonstop flight takes 1 hour(s) 59 minutes, with the flight distance of 1074 km (667 miles).
What type of aircraft is used for the Allegiant Air G41050 flight?
All Allegiant Air G41050 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41050 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41050 is operated on Friday.
