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Allegiant Air G41428 flight status now
G41428 - AAY1428
Allegiant Air (G4)
JAX
Jacksonville United States
TYS
Knoxville United States
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It may not operate on the date requested
G41428 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 18 minutes
- Flight Distance: 627 kms / 390 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A320
- Callsign: F-KPGD2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Jacksonville: Wednesday 2025-11-19 02:31 AM
- Current Time in Knoxville: Wednesday 2025-11-19 02:31 AM
Domestic flight Allegiant Air G41428 takes off from Jacksonville (JAX) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves Jacksonville International Airport at 15:26 America/New_York. The flight is expected to land at McGhee Tyson Airport at 16:44 America/New_York. The flight will last about 1 hours 18 minutes.
Frequently asked questions, answered
How long is the flight from Jacksonville to Knoxville?
On average, nonstop flight takes 1 hour(s) 18 minutes, with the flight distance of 627 km (390 miles).
What type of aircraft is used for the Allegiant Air G41428 flight?
All Allegiant Air G41428 flights are operated using Airbus A320 aircraft.
How many Allegiant Air G41428 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41428 is operated on Thursday.
