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Allegiant Air G41428 Flight Status Today
Domestic flight Allegiant Air G41428 takes off from Jacksonville (JAX) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves Jacksonville International Airport at 19:33 03 May 2026 America/New_York. The flight is expected to land at McGhee Tyson Airport at 21:12 03 May 2026 America/New_York. The flight will last about 1 hours 39 minutes.
Current status of G41428 is Scheduled On time Expected Depart in 6 hours, 50 minutes
G41428 - AAY1428
Allegiant Air (G4)
JAX
Jacksonville United States
TYS
Knoxville United States
Scheduled On time
Expected Depart in 6 hours, 50 minutes
G41428 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 39 minutes
- Flight Distance: 627 kms / 390 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KPGD2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Jacksonville: Sunday 2026-05-03 12:43 PM
- Current Time in Knoxville: Sunday 2026-05-03 12:43 PM
Flight routes similar to Allegiant Air G41428
Allegiant Air Flight G41428 FAQs
What is the scheduled flight duration for Allegiant Air G41428 flight?
On average, nonstop flight takes 1 hour(s) 39 minutes, with the flight distance of 627 km (390 miles).
What is the current status of Allegiant Air G41428 flight?
The current status of flight Allegiant Air G41428 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G41428 flight?
All Allegiant Air G41428 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G41428 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41428 is operated on Thursday.