Allegiant Air G41403 Flight Status Today

Domestic flight Allegiant Air G41403 takes off from Jacksonville (JAX) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves Jacksonville International Airport at 20:01 America/New_York. The flight is expected to land at McGhee Tyson Airport at 21:27 America/New_York. The flight will last about 1 hours 26 minutes.

G41403 - AAY1403 Allegiant Air (G4)
JAX Jacksonville United States
Flight JAX to TYS
TYS Knoxville United States
Contact Airlines It may not operate on the date requested
Departure Jacksonville International Airport
IATA: JAXICAO: KJAX
Scheduled 20:01
None C6
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 21:27
None 6
G41403 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 26 minutes
  • Flight Distance: 627 kms / 390 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KCSV2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Jacksonville: Sunday 2026-03-22 14:01 PM
  • Current Time in Knoxville: Sunday 2026-03-22 14:01 PM

Flight routes similar to Allegiant Air G41403

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Allegiant Air G41423
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Allegiant Air G43031
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Allegiant Air G41428
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Allegiant Air G41437
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Allegiant Air Flight G41403 FAQs

What is the scheduled flight duration for Allegiant Air G41403 flight?

On average, nonstop flight takes 1 hour(s) 26 minutes, with the flight distance of 627 km (390 miles).

What type of aircraft is used for the Allegiant Air G41403 flight?

All Allegiant Air G41403 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G41403 flights are operated a week?

2 flights per week. The Flight Allegiant Air G41403 is operated on Thursday, Sunday.