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Allegiant Air G41375 Flight Status Today
Domestic flight Allegiant Air G41375 takes off from Sarasota (SRQ) United States to Fort Wayne (FWA) United States. It's operated by Allegiant Air. The plane leaves Sarasota Bradenton International Airport at 06:31 America/New_York. The flight is expected to land at Fort Wayne International Airport at 09:06 America/Indiana/Indianapolis. The flight will last about 2 hours 41 minutes.
G41375 - AAY1375
Allegiant Air (G4)
SRQ
Sarasota United States
FWA
Fort Wayne United States
Contact Airlines
It may not operate on the date requested
G41375 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 41 minutes
- Flight Distance: 1528 kms / 949 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A320
- Callsign: F-KSRQ2
- Departure Timezone: America/New_York
- Arrival Timezone: America/Indiana/Indianapolis
- Current Time in Sarasota: Monday 2026-03-02 09:11 AM
- Current Time in Fort Wayne: Monday 2026-03-02 09:11 AM
Flight routes similar to Allegiant Air G41375
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G41388 Allegiant Air |
02/03/2026 13:57 |
2 hours 26 minutes 16:31 |
Allegiant Air Flight G41375 FAQs
What is the scheduled flight duration for Allegiant Air G41375 flight?
On average, nonstop flight takes 2 hour(s) 41 minutes, with the flight distance of 1528 km (949 miles).
What type of aircraft is used for the Allegiant Air G41375 flight?
All Allegiant Air G41375 flights are operated using Airbus A320 aircraft.
How many Allegiant Air G41375 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41375 is operated on Monday.
