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Allegiant Air G41375 Flight Status Today
Domestic flight Allegiant Air G41375 takes off from Sarasota (SRQ) United States to Fort Wayne (FWA) United States. It's operated by Allegiant Air. The plane leaves Sarasota Bradenton International Airport at 08:01 22 March 2026 America/New_York. The flight is expected to land at Fort Wayne International Airport at 09:48 22 March 2026 America/Indiana/Indianapolis. The flight will last about 2 hours 32 minutes.
Current status of G41375 is Arrived On time
- Type: Domestic Flight
- Flight Duration: 2 hours 32 minutes
- Flight Distance: 1528 kms / 949 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320
- Callsign: F-KSRQ2
- Departure Timezone: America/New_York
- Arrival Timezone: America/Indiana/Indianapolis
- Current Time in Sarasota: Sunday 2026-03-22 21:37 PM
- Current Time in Fort Wayne: Sunday 2026-03-22 21:37 PM
Flight routes similar to Allegiant Air G41375
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G43004 Allegiant Air |
22/03/2026 06:01 |
2 hours 35 minutes 08:36 |
Allegiant Air Flight G41375 FAQs
What is the scheduled flight duration for Allegiant Air G41375 flight?
On average, nonstop flight takes 2 hour(s) 32 minutes, with the flight distance of 1528 km (949 miles).
What is the current status of Allegiant Air G41375 flight?
The current status of flight Allegiant Air G41375 is Arrived On time.
What type of aircraft is used for the Allegiant Air G41375 flight?
All Allegiant Air G41375 flights are operated using Airbus A320 aircraft.
How many Allegiant Air G41375 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41375 is operated on Monday.
