JetBlue Airways B62041 Flight Status Today

Domestic flight JetBlue Airways B62041 takes off from Boston (BOS) United States to Cleveland (CLE) United States. It's operated by JetBlue Airways. The plane leaves Logan International Airport at 21:30 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 23:40 America/New_York. The flight will last about 2 hours 10 minutes.

B62041 - JBU2041 JetBlue Airways (B6)
BOS Boston United States
Flight BOS to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 21:30
C C22
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 23:40
None C6
B62041 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 10 minutes
  • Flight Distance: 903 kms / 561 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A220-300 Passenger
  • Callsign: F-KCLE4
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Wednesday 2026-02-11 14:59 PM
  • Current Time in Cleveland: Wednesday 2026-02-11 14:59 PM

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JetBlue Airways Flight B62041 FAQs

What is the scheduled flight duration for JetBlue Airways B62041 flight?

On average, nonstop flight takes 2 hour(s) 10 minutes, with the flight distance of 903 km (561 miles).

What type of aircraft is used for the JetBlue Airways B62041 flight?

All JetBlue Airways B62041 flights are operated using Airbus A220-300 Passenger aircraft.

How many JetBlue Airways B62041 flights are operated a week?

6 flights per week. The Flight JetBlue Airways B62041 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Sunday.