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Allegiant Air G41075 Flight Status Today
Domestic flight Allegiant Air G41075 takes off from Kansas City (MCI) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Kansas City International Airport at 08:59 08 February 2026 America/Chicago. The flight is expected to land at St. Petersburg-Clearwater International Airport at 12:31 08 February 2026 America/New_York. The flight will last about 2 hours 32 minutes.
Current status of G41075 is Departed On time Estimated Arrival in 23 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 32 minutes
- Flight Distance: 1682 kms / 1045 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A319
- Callsign: F-KVDF2
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Kansas City: Sunday 2026-02-08 10:41 AM
- Current Time in Saint Petersburg: Sunday 2026-02-08 11:41 AM
Flight routes similar to Allegiant Air G41075
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G42714 Allegiant Air |
08/02/2026 08:59 |
2 hours 32 minutes 12:31 |
Allegiant Air Flight G41075 FAQs
What is the scheduled flight duration for Allegiant Air G41075 flight?
On average, nonstop flight takes 2 hour(s) 32 minutes, with the flight distance of 1682 km (1045 miles).
What is the current status of Allegiant Air G41075 flight?
The current status of flight Allegiant Air G41075 is Departed On time.
What type of aircraft is used for the Allegiant Air G41075 flight?
All Allegiant Air G41075 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41075 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41075 is operated on Sunday.
