Allegiant Air G41047 Flight Status Today

Domestic flight Allegiant Air G41047 takes off from Huntington (HTS) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Tri-State/Milton Airport at 14:44 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 16:40 America/New_York. The flight will last about 1 hours 56 minutes.

G41047 - AAY1047 Allegiant Air (G4)
HTS Huntington United States
Flight HTS to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Tri-State/Milton Airport
IATA: HTSICAO: KHTS
Scheduled 14:44
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 16:40
None 10
G41047 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 56 minutes
  • Flight Distance: 1160 kms / 721 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: F-KTLH2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Huntington: Thursday 2026-01-01 00:58 AM
  • Current Time in Saint Petersburg: Thursday 2026-01-01 00:58 AM

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Allegiant Air Flight G41047 FAQs

What is the scheduled flight duration for Allegiant Air G41047 flight?

On average, nonstop flight takes 1 hour(s) 56 minutes, with the flight distance of 1160 km (721 miles).

What type of aircraft is used for the Allegiant Air G41047 flight?

All Allegiant Air G41047 flights are operated using Airbus A319 aircraft.

How many Allegiant Air G41047 flights are operated a week?

2 flights per week. The Flight Allegiant Air G41047 is operated on Saturday, Sunday.