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Allegiant Air G41022 Flight Status Today
Domestic flight Allegiant Air G41022 takes off from Saint Petersburg (PIE) United States to Columbus (LCK) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 07:00 America/New_York. The flight is expected to land at Rickenbacker International Airport at 09:15 America/New_York. The flight will last about 2 hours 15 minutes.
G41022 - AAY1022
Allegiant Air (G4)
PIE
Saint Petersburg United States
LCK
Columbus United States
Contact Airlines
It may not operate on the date requested
Scheduled
07:00
None
2
G41022 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 15 minutes
- Flight Distance: 1321 kms / 821 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Saturday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KMLI3
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Sunday 2026-05-03 20:34 PM
- Current Time in Columbus: Sunday 2026-05-03 20:34 PM
Allegiant Air Flight G41022 FAQs
What is the scheduled flight duration for Allegiant Air G41022 flight?
On average, nonstop flight takes 2 hour(s) 15 minutes, with the flight distance of 1321 km (821 miles).
What type of aircraft is used for the Allegiant Air G41022 flight?
All Allegiant Air G41022 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41022 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41022 is operated on Saturday.
