Check your Flight status online
Allegiant Air G41040 Flight Status
- Type: Domestic Flight
- Flight Duration: 2 hours 28 minutes
- Flight Distance: 1468 kms / 912 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Saturday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KRDU1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Middletown: Monday 2025-12-08 21:07 PM
- Current Time in Saint Petersburg: Monday 2025-12-08 21:07 PM
Domestic flight Allegiant Air G41040 takes off from Middletown (MDT) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Harrisburg International Airport at 20:20 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 22:48 America/New_York. The flight will last about 2 hours 28 minutes.
Similar flight route from Middletown (MDT) to Saint Petersburg (PIE)
Frequently asked questions, answered
What is the scheduled flight duration for Allegiant Air G41040 flight?
On average, nonstop flight takes 2 hour(s) 28 minutes, with the flight distance of 1468 km (912 miles).
What type of aircraft is used for the Allegiant Air G41040 flight?
All Allegiant Air G41040 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G41040 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41040 is operated on Saturday.
