Allegiant Air G41040 Flight Status Today

Domestic flight Allegiant Air G41040 takes off from Saint Petersburg (PIE) United States to Columbus (LCK) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 06:00 America/New_York. The flight is expected to land at Rickenbacker International Airport at 08:17 America/New_York. The flight will last about 1 hours 54 minutes.

G41040 - AAY1040 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to LCK
LCK Columbus United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 06:00
None 10
Arrival Rickenbacker International Airport
IATA: LCKICAO: KLCK
Scheduled 08:17
None 1
G41040 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 54 minutes
  • Flight Distance: 1321 kms / 821 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: F-KRDU1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Sunday 2026-03-22 08:45 AM
  • Current Time in Columbus: Sunday 2026-03-22 08:45 AM

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Allegiant Air Flight G41040 FAQs

What is the scheduled flight duration for Allegiant Air G41040 flight?

On average, nonstop flight takes 1 hour(s) 54 minutes, with the flight distance of 1321 km (821 miles).

What type of aircraft is used for the Allegiant Air G41040 flight?

All Allegiant Air G41040 flights are operated using Airbus A319 aircraft.

How many Allegiant Air G41040 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41040 is operated on Saturday.