Allegiant Air G41012 Flight Status Today

Domestic flight Allegiant Air G41012 takes off from Hagerstown (HGR) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Wash. County Regional Airport at 09:27 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 11:52 America/New_York. The flight will last about 2 hours 12 minutes.

G41012 - AAY1012 Allegiant Air (G4)
HGR Hagerstown United States
Flight HGR to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Wash. County Regional Airport
IATA: HGRICAO: KHGR
Scheduled 09:27
None A2
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 11:52
None 9
G41012 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 12 minutes
  • Flight Distance: 1386 kms / 861 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: F-KBPK2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Hagerstown: Sunday 2026-05-03 18:57 PM
  • Current Time in Saint Petersburg: Sunday 2026-05-03 18:57 PM

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Allegiant Air Flight G41012 FAQs

What is the scheduled flight duration for Allegiant Air G41012 flight?

On average, nonstop flight takes 2 hour(s) 12 minutes, with the flight distance of 1386 km (861 miles).

What type of aircraft is used for the Allegiant Air G41012 flight?

All Allegiant Air G41012 flights are operated using Airbus A319 aircraft.

How many Allegiant Air G41012 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41012 is operated on Sunday.