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Allegiant Air G41012 Flight Status Today
Domestic flight Allegiant Air G41012 takes off from Saint Petersburg (PIE) United States to Chattanooga (CHA) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 19:38 19 January 2026 America/New_York. The flight is expected to land at Chattanooga Airport at 23:18 19 January 2026 America/New_York. The flight will last about 2 hours 40 minutes.
Current status of G41012 is Scheduled On time Expected Depart in 3 hours, 17 minutes
G41012 - AAY1012
Allegiant Air (G4)
PIE
Saint Petersburg United States
CHA
Chattanooga United States
Scheduled On time
Expected Depart in 3 hours, 17 minutes
Scheduled
19:38 19 January 2026
None
None
G41012 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 40 minutes
- Flight Distance: 825 kms / 513 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Sunday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Airbus A319
- Callsign: F-KBPK2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Monday 2026-01-19 16:21 PM
- Current Time in Chattanooga: Monday 2026-01-19 16:21 PM
Allegiant Air Flight G41012 FAQs
What is the scheduled flight duration for Allegiant Air G41012 flight?
On average, nonstop flight takes 2 hour(s) 40 minutes, with the flight distance of 825 km (513 miles).
What is the current status of Allegiant Air G41012 flight?
The current status of flight Allegiant Air G41012 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G41012 flight?
All Allegiant Air G41012 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41012 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41012 is operated on Sunday.