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Allegiant Air G42640 Flight Status Today
Domestic flight Allegiant Air G42640 takes off from Saint Petersburg (PIE) United States to Akron (CAK) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 17:37 America/New_York. The flight is expected to land at Akron-Canton Airport at 20:01 America/New_York. The flight will last about 2 hours 24 minutes.
G42640 - AAY2640
Allegiant Air (G4)
PIE
Saint Petersburg United States
CAK
Akron United States
Contact Airlines
It may not operate on the date requested
Scheduled
17:37
None
9
G42640 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 24 minutes
- Flight Distance: 1447 kms / 899 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KVDF2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Sunday 2026-03-01 16:49 PM
- Current Time in Akron: Sunday 2026-03-01 16:49 PM
Allegiant Air Flight G42640 FAQs
What is the scheduled flight duration for Allegiant Air G42640 flight?
On average, nonstop flight takes 2 hour(s) 24 minutes, with the flight distance of 1447 km (899 miles).
What type of aircraft is used for the Allegiant Air G42640 flight?
All Allegiant Air G42640 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G42640 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42640 is operated on Thursday.
