FedEx FX7678 Flight Status Today

Domestic flight FedEx FX7678 takes off from Portland (PDX) United States to Medford (MFR) United States. It's operated by FedEx Express. The plane leaves Portland International Airport at 08:45 America/Los_Angeles. The flight is expected to land at Rogue Valley International-Medford Airport at None America/Los_Angeles. The flight will last about 1 hours 15 minutes.

FX7678 - FDX7678 FedEx Express (FX)
PDX Portland United States
Flight PDX to MFR
MFR Medford United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Portland International Airport
IATA: PDXICAO: KPDX
Scheduled 08:45
None None
Arrival Rogue Valley International-Medford Airport
IATA: MFRICAO: KMFR
Scheduled None
None None
FX7678 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 15 minutes
  • Flight Distance: 358 kms / 223 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Cessna 208B Super Cargomaster
  • Callsign: CFS7678
  • Departure Timezone: America/Los_Angeles
  • Arrival Timezone: America/Los_Angeles
  • Current Time in Portland: Wednesday 2025-12-31 00:56 AM
  • Current Time in Medford: Wednesday 2025-12-31 00:56 AM

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FedEx Flight FX7678 FAQs

What is the scheduled flight duration for FedEx FX7678 flight?

On average, nonstop flight takes 1 hour(s) 15 minutes, with the flight distance of 358 km (223 miles).

What type of aircraft is used for the FedEx FX7678 flight?

All FedEx FX7678 flights are operated using Cessna 208B Super Cargomaster aircraft.