FedEx FX7673 Flight Status Today

Domestic flight FedEx FX7673 takes off from Medford (MFR) United States to Portland (PDX) United States. It's operated by FedEx Express. The plane leaves Rogue Valley International-Medford Airport at 17:27 America/Los_Angeles. The flight is expected to land at Portland International Airport at None America/Los_Angeles. The flight will last about 58 minutes.

FX7673 - FDX7673 FedEx Express (FX)
MFR Medford United States
Flight MFR to PDX
PDX Portland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Rogue Valley International-Medford Airport
IATA: MFRICAO: KMFR
Scheduled 17:27
None None
Arrival Portland International Airport
IATA: PDXICAO: KPDX
Scheduled None
None None
FX7673 Detail
  • Type: Domestic Flight
  • Flight Duration: 58 minutes
  • Flight Distance: 358 kms / 223 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: ATR 72-212(F)
  • Callsign: CFS7673
  • Departure Timezone: America/Los_Angeles
  • Arrival Timezone: America/Los_Angeles
  • Current Time in Medford: Saturday 2026-05-02 04:30 AM
  • Current Time in Portland: Saturday 2026-05-02 04:30 AM

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FedEx Flight FX7673 FAQs

What is the scheduled flight duration for FedEx FX7673 flight?

On average, nonstop flight takes 58 minutes, with the flight distance of 358 km (223 miles).

What type of aircraft is used for the FedEx FX7673 flight?

All FedEx FX7673 flights are operated using ATR 72-212(F) aircraft.