FedEx FX3740 Flight Status Today

Domestic flight FedEx FX3740 takes off from Indianapolis (IND) United States to Charlotte (CLT) United States. It's operated by FedEx Express. The plane leaves Indianapolis International Airport at 16:25 America/Indiana/Indianapolis. The flight is expected to land at Charlotte Douglas International Airport at 17:33 America/New_York. The flight will last about 1 hours 16 minutes.

FX3740 - FDX3740 FedEx Express (FX)
IND Indianapolis United States
Flight IND to CLT
CLT Charlotte United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 16:25
None None
Arrival Charlotte Douglas International Airport
IATA: CLTICAO: KCLT
Scheduled 17:33
None None
FX3740 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 16 minutes
  • Flight Distance: 688 kms / 427 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 767-300 Freighter
  • Callsign: None
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Friday 2026-04-10 14:13 PM
  • Current Time in Charlotte: Friday 2026-04-10 14:13 PM

Flight routes similar to FedEx FX3740

Airline Flight no Departure Arrival
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Spirit Airlines NK1904
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Spirit Airlines NK2363
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22:59

FedEx Flight FX3740 FAQs

What is the scheduled flight duration for FedEx FX3740 flight?

On average, nonstop flight takes 1 hour(s) 16 minutes, with the flight distance of 688 km (427 miles).

What type of aircraft is used for the FedEx FX3740 flight?

All FedEx FX3740 flights are operated using Boeing 767-300 Freighter aircraft.