FedEx FX3705 Flight Status Today

Domestic flight FedEx FX3705 takes off from Indianapolis (IND) United States to New York (JFK) United States. It's operated by FedEx Express. The plane leaves Indianapolis International Airport at 19:21 America/Indiana/Indianapolis. The flight is expected to land at John F. Kennedy International Airport at 21:03 America/New_York. The flight will last about 4 hours 7 minutes.

FX3705 - FDX3705 FedEx Express (FX)
IND Indianapolis United States
Flight IND to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 27-February-2021
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 19:21
None None
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 21:03
None None
FX3705 Detail
  • Type: Domestic Flight
  • Flight Duration: 4 hours 7 minutes
  • Flight Distance: 1069 kms / 664 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: M11
  • Callsign: None
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Monday 2025-12-29 11:54 AM
  • Current Time in New York: Monday 2025-12-29 11:54 AM

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FedEx Flight FX3705 FAQs

What is the scheduled flight duration for FedEx FX3705 flight?

On average, nonstop flight takes 4 hour(s) 7 minutes, with the flight distance of 1069 km (664 miles).

What type of aircraft is used for the FedEx FX3705 flight?

All FedEx FX3705 flights are operated using M11 aircraft.