FedEx FX3460 Flight Status Today

Domestic flight FedEx FX3460 takes off from Charlotte (CLT) United States to Indianapolis (IND) United States. It's operated by FedEx Express. The plane leaves Charlotte Douglas International Airport at 11:44 America/New_York. The flight is expected to land at Indianapolis International Airport at None America/Indiana/Indianapolis. The flight will last about 1 hours 10 minutes.

FX3460 - FDX3460 FedEx Express (FX)
CLT Charlotte United States
Flight CLT to IND
IND Indianapolis United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Charlotte Douglas International Airport
IATA: CLTICAO: KCLT
Scheduled 11:44
None None
Arrival Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled None
None None
FX3460 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 688 kms / 427 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A300B4-622R(F)
  • Callsign: FDX3460
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Indiana/Indianapolis
  • Current Time in Charlotte: Monday 2026-01-19 19:23 PM
  • Current Time in Indianapolis: Monday 2026-01-19 19:23 PM

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FedEx Flight FX3460 FAQs

What is the scheduled flight duration for FedEx FX3460 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 688 km (427 miles).

What type of aircraft is used for the FedEx FX3460 flight?

All FedEx FX3460 flights are operated using Airbus A300B4-622R(F) aircraft.