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FedEx FX1455 Flight Status Today
Domestic flight FedEx FX1455 takes off from Memphis (MEM) United States to Jacksonville (JAX) United States. It's operated by FedEx Express. The plane leaves Memphis International Airport at 03:43 27 February 2026 America/Chicago. The flight is expected to land at Jacksonville International Airport at 06:55 27 February 2026 America/New_York. The flight will last about 1 hours 26 minutes.
Current status of FX1455 is Arrived On time
FX1455 - FDX1455
FedEx Express (FX)
MEM
Memphis United States
JAX
Jacksonville United States
Arrived On time
Scheduled
03:43 27 February 2026
Actual
04:41 27 February 2026
None
None
Scheduled
06:55 27 February 2026
Actual
07:07 27 February 2026
None
None
FX1455 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 26 minutes
- Flight Distance: 927 kms / 576 miles
Airline
- FedEx Express
- IATA: FX
- ICAO: FDX
- Operating Days: Tuesday, Wednesday, Thursday, Friday, Saturday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Boeing 767-300 Freighter
- Callsign: F-KOLV2
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Memphis: Friday 2026-02-27 15:49 PM
- Current Time in Jacksonville: Friday 2026-02-27 16:49 PM
FedEx Flight FX1455 FAQs
What is the scheduled flight duration for FedEx FX1455 flight?
On average, nonstop flight takes 1 hour(s) 26 minutes, with the flight distance of 927 km (576 miles).
What is the current status of FedEx FX1455 flight?
The current status of flight FedEx FX1455 is Arrived On time.
What type of aircraft is used for the FedEx FX1455 flight?
All FedEx FX1455 flights are operated using Boeing 767-300 Freighter aircraft.
How many FedEx FX1455 flights are operated a week?
5 flights per week. The Flight FedEx FX1455 is operated on Tuesday, Wednesday, Thursday, Friday, Saturday.