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FedEx FX1287 Flight Status Today
Domestic flight FedEx FX1287 takes off from Cleveland (CLE) United States to Louisville (SDF) United States. It's operated by FedEx Express. The plane leaves Cleveland Hopkins International Airport at 19:58 America/New_York. The flight is expected to land at Louisville International Airport-Standiford Field at 20:47 America/New_York. The flight will last about 0 minutes.
- Type: Domestic Flight
- Flight Duration: 0 minutes
- Flight Distance: 490 kms / 305 miles
- FedEx Express
- IATA: FX
- ICAO: FDX
- Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Boeing 757-200 Freighter (winglets)
- Callsign: T-KCOS8
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Cleveland: Thursday 2026-01-01 11:34 AM
- Current Time in Louisville: Thursday 2026-01-01 11:34 AM
FedEx Flight FX1287 FAQs
What is the scheduled flight duration for FedEx FX1287 flight?
On average, nonstop flight takes 0 minutes, with the flight distance of 490 km (305 miles).
What type of aircraft is used for the FedEx FX1287 flight?
All FedEx FX1287 flights are operated using Boeing 757-200 Freighter (winglets) aircraft.
How many FedEx FX1287 flights are operated a week?
5 flights per week. The Flight FedEx FX1287 is operated on Monday, Tuesday, Wednesday, Thursday, Friday.
