JetBlue Airways B66373 Flight Status Today

Domestic flight JetBlue Airways B66373 takes off from New York (JFK) United States to Cleveland (CLE) United States. It's operated by JetBlue Airways. The plane leaves John F. Kennedy International Airport at 13:00 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 14:47 America/New_York. The flight will last about 4 hours 49 minutes.

B66373 - JBU6373 JetBlue Airways (B6)
JFK New York United States
Flight JFK to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 06-February-2020
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 13:00
C C17
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 14:47
USA DEP 3
B66373 Detail
  • Type: Domestic Flight
  • Flight Duration: 4 hours 49 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Sunday 2026-01-18 11:09 AM
  • Current Time in Cleveland: Sunday 2026-01-18 11:09 AM

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JetBlue Airways Flight B66373 FAQs

What is the scheduled flight duration for JetBlue Airways B66373 flight?

On average, nonstop flight takes 4 hour(s) 49 minutes, with the flight distance of 682 km (424 miles).

Which terminal the flight JetBlue Airways B66373 is arriving at?

Flight JetBlue Airways B66373 arrives in Cleveland Hopkins International Airport at Terminal USA DEP.